What is the product of the following reaction?

Assertion: Only a small amount of $HCl$ is required in the reduction of nitro compounds with iron scrap.
Reason: $FeCl_2$ formed gets hydrolysed to release $HCl$ during the reaction.

$RCONH_2$ is converted into $RNH_2$ by means of Hofmann bromamide degradation. In this reaction,$RCONHBr$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.
$1.$ How can the conversion of $(i)$ to $(ii)$ be brought about?
$(A)$ $KBr$
$(B)$ $KBr + CH_3ONa$
$(C)$ $KBr + KOH$
$(D)$ $Br_2 + KOH$
$2.$ Which is the rate determining step in Hofmann bromamide degradation?
$(A)$ Formation of $(i)$
$(B)$ Formation of $(ii)$
$(C)$ Formation of $(iii)$
$(D)$ Formation of $(iv)$
$3.$ What are the constituent amines formed when the mixture of $(i)$ and $(ii)$ undergoes Hofmann bromamide degradation?
Give the answer for question $1$,$2$,and $3$.

Give the structure of $A$ in the following reaction.
$2\text{-Nitro-4-methylaniline} \xrightarrow[(ii) \ H_3PO_2, H_2O]{(i) NaNO_2 + HCl, 273 - 278 \ K} A$.

Benzene diazonium chloride on reaction with ethanol forms

The major product $(R)$ of the following reaction is:
$C_6H_5NH_2$ $\xrightarrow[{0 \, ^\circ C}]{{HNO_2}} P$ $\xrightarrow{{HBF_4}} Q$ $\xrightarrow[{Cu, \, \Delta }]{{NaNO_2}} R$